(i) (a) Correct Option: (C)
- Step 1 (Conceptual Analysis): [0.5 Mark]
According to the band theory and semiconductor physics, in an n-type semiconductor, the pentavalent impurity atoms donate extra electrons. Therefore, electrons are the majority charge carriers, and holes are the minority charge carriers.
- Step 2 (Verification of Statements): [0.25 Mark]
- (A) True: In intrinsic semiconductors, $R \propto e^{E_g/2kT}$, so resistance decreases as temperature increases.
- (B) True: Trivalent impurities (e.g., Boron) create holes, resulting in p-type semiconductors.
- (C) False: In n-type semiconductors, electrons are the majority carriers, not holes.
- (D) True: A p-n junction diode allows current flow in one direction, acting as a rectifier.
- Step 3 (Final Concluded Answer): [0.25 Mark]
The statement that is not true is (C).
OR
(i) (b) Correct Option: (D)
- Step 1 (Governing Principle): [0.5 Mark]
In an unbiased p-n junction, the concentration gradient causes diffusion of charge carriers, creating an electric field. This field causes drift of carriers. At equilibrium, the net current $I_{net} = I_{diffusion} + I_{drift} = 0$.
- Step 2 (Mathematical Working): [0.25 Mark]
Since the junction is in equilibrium (unbiased), the rate of charge transfer due to diffusion is exactly balanced by the rate of charge transfer due to the internal electric field (drift):
$$I_{diffusion} = -I_{drift}$$ $$\implies I_{diffusion} + I_{drift} = 0$$ - Step 3 (Final Concluded Answer): [0.25 Mark]
The correct statement is (D): the drift current and the diffusion current cancel each other.
💡 EL10 Concept Insight: Think of an unbiased p-n junction like a room with two doors: diffusion is like people walking from a crowded side to an empty side, while drift is like a security guard pushing them back; when the number of people crossing equals the number being pushed back, the room stays perfectly balanced!