Correct Option: (B) $\nu_{\text{G}} > \nu_{\text{X}} > \nu_{\text{U}}$
Step 1 (Governing Law & Electromagnetic Spectrum Order): [0.5 Mark]
The electromagnetic spectrum is arranged in order of increasing frequency (or decreasing wavelength). According to the standard NCERT electromagnetic spectrum classification, the frequencies follow the order:
$$ \nu_{\text{Radio}} < \nu_{\text{Microwave}} < \nu_{\text{Infrared}} < \nu_{\text{Visible}} < \nu_{\text{UV}} < \nu_{\text{X-rays}} < \nu_{\text{Gamma-rays}} $$Step 2 (Step-by-Step Comparison): [0.25 Mark]
Based on the established sequence of the electromagnetic spectrum, we compare the three given radiations:
- Gamma-rays ($\nu_{\text{G}}$) have the highest frequency among the three.
- X-rays ($\nu_{\text{X}}$) have a frequency lower than Gamma-rays but higher than UV rays.
- UV rays ($\nu_{\text{U}}$) have the lowest frequency among the three.
Therefore, the inequality holds as: $\nu_{\text{G}} > \nu_{\text{X}} > \nu_{\text{U}}$.
Step 3 (Final Concluded Answer): [0.25 Mark]
Comparing the derived inequality with the given options, we conclude that the correct relationship is:
$$ \nu_{\text{G}} > \nu_{\text{X}} > \nu_{\text{U}} $$This corresponds to Option (B).
💡 EL10 Concept Insight: Think of the electromagnetic spectrum like a musical scale; Gamma-rays are the "highest pitch" (highest frequency) notes, while X-rays are a bit lower, and UV rays are lower still. Just remember that the more dangerous and energetic the radiation is, the higher its frequency!