Physics Ray Optics and Optical Instruments 3 Marks
Appeared in: 2026 (3 sets)
An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified. (i) The images formed by the objective lens and the eyepiece are respectively : (A) virtual, real (B) real, virtual (C) virtual, virtual (D) real, real (ii) The magnification produced by the telescope does not depend upon the : (A) colour of light (B) focal length of objective lens (C) focal length of eyepiece (D) apertures of objective lens and eyepiece (iii) Which of the following statements is not correct for this telescope ? (A) The focal length of objective lens ($f_o$) is larger than the focal length of eyepiece ($f_e$). (B) Its magnifying power can be increased by increasing the focal length of objective lens ($f_o$). (C) The distance between two lenses is more than ($f_o + f_e$). (D) The magnifying power can be decreased by increasing the focal length of eyepiece.
✓ Verified CBSE Marking Scheme Official Evaluation Steps & EL10 Insight

CBSE Class 12 Physics: Astronomical Telescope Marking Scheme

(i) The images formed by the objective lens and the eyepiece are respectively:

Step 1 (Governing Principle): [0.5 Mark]
In an astronomical telescope, the objective lens forms a real, inverted, and diminished image of a distant object at its focal plane. This image acts as a real object for the eyepiece, which then acts as a simple magnifier to form a virtual, magnified final image.

Step 2 (Deduction): [0.5 Mark]
Objective lens: Real image. Eyepiece: Virtual image.

Step 3 (Final Answer): [0 Mark]
Correct Option: (B) real, virtual


(ii) The magnification produced by the telescope does not depend upon the:

Step 1 (Governing Formula): [0.5 Mark]
The magnifying power ($m$) of an astronomical telescope in normal adjustment is given by: $$m = -\frac{f_o}{f_e}$$ where $f_o$ is the focal length of the objective and $f_e$ is the focal length of the eyepiece.

Step 2 (Analysis): [0.5 Mark]
The formula shows that $m$ depends on $f_o$ and $f_e$. The aperture determines the light-gathering power (brightness) and resolving power, but does not affect the angular magnification ($m$).

Step 3 (Final Answer): [0 Mark]
Correct Option: (D) apertures of objective lens and eyepiece


(iii) Which of the following statements is not correct for this telescope?

Step 1 (Governing Principle): [0.5 Mark]
For a telescope in normal adjustment, the length of the tube ($L$) is: $$L = f_o + f_e$$

Step 2 (Evaluation of Statements): [0.5 Mark]

  • (A) Correct: $f_o > f_e$ is required for magnification.
  • (B) Correct: Since $m = f_o/f_e$, increasing $f_o$ increases $m$.
  • (C) Incorrect: The distance between lenses is exactly $(f_o + f_e)$ in normal adjustment, not "more than".
  • (D) Correct: Increasing $f_e$ decreases the ratio $f_o/f_e$.

Step 3 (Final Answer): [0 Mark]
Correct Option: (C) The distance between two lenses is more than $(f_o + f_e)$.


💡 EL10 Concept Insight:
Think of the objective lens as a "light bucket" that captures a tiny, real picture of a far-away star, and the eyepiece as a magnifying glass that you use to look closely at that tiny picture to make it look huge to your eye.