Calculate emf of the following cell at $298\text{ K}$ : $\text{Mg(s)} \mid \text{Mg}^{2+} (0.001\text{ M}) \parallel \text{Cu}^{2+} (0.0001\text{ M}) \mid \text{Cu(s)}$ Given : $E^\circ_{\text{cell}} = 2.71\text{ V}$, $\log 10 = 1$