Physics Unclassified 1 Mark
Appeared in: 2026 (3 sets)
Four independent waves are expressed as (i) $y_1 = A_1 \sin \omega t$ (ii) $y_2 = A_2 \sin 2\omega t$ (iii) $y_3 = A_3 \cos \omega t$ (iv) $y_4 = A_4 \sin $\omega t + \pi/3$$ The interference between two of these waves is possible in (A) (i) and (iii) only (B) (iii) and (iv) only (C) (i), (iii) and (iv) only (D) All of them
✓ Verified CBSE Marking Scheme Official Evaluation Steps & EL10 Insight

Step 1 (Governing Law & Condition for Interference): [0.25 Mark]

For two waves to produce a stable interference pattern, they must be coherent. The fundamental condition for coherence is that the waves must have the same frequency (or same angular frequency, $\omega$).

Given waves:

  • (i) $y_1 = A_1 \sin \omega t$ (Frequency: $\omega$)
  • (ii) $y_2 = A_2 \sin 2\omega t$ (Frequency: $2\omega$)
  • (iii) $y_3 = A_3 \cos \omega t = A_3 \sin(\omega t + \pi/2)$ (Frequency: $\omega$)
  • (iv) $y_4 = A_4 \sin(\omega t + \pi/3)$ (Frequency: $\omega$)

Step 2 (Step-by-Step Mathematical Working): [0.5 Mark]

We compare the angular frequencies of the given waves:

  • Wave (i), (iii), and (iv) all possess the same angular frequency, $\omega$.
  • Wave (ii) has an angular frequency of $2\omega$, which is different from the others.

Since interference requires the same frequency, waves (i), (iii), and (iv) can interfere with each other because they satisfy the condition:

$$\omega_1 = \omega_3 = \omega_4 = \omega$$

Wave (ii) cannot interfere with any of the others because $2\omega \neq \omega$.

Step 3 (Final Concluded Answer): [0.25 Mark]

The waves that can interfere are (i), (iii), and (iv). Therefore, the correct option is (C).

💡 EL10 Concept Insight:

Think of interference like two people trying to dance in sync; if one person is dancing at a different speed (frequency) than the other, they can never stay in step to create a steady pattern. Only waves moving at the exact same speed can "lock in" to create a consistent interference pattern!