If $\frac{\text{d}}{\text{dx}} \text{f}(x) = 3x^2 - \frac{3}{x^4}$ such that $\text{f}(1) = 0$, then $\text{f}(x)$ is : (A) $6x + \frac{12}{x^5}$ (B) $x^4 - \frac{1}{x^3} + 2$ (C) $x^3 + \frac{1}{x^3} - 2$ (D) $x^3 + \frac{1}{x^3} + 2$