Question Analysis: To produce a stable interference pattern, the two light waves must be coherent. Coherent sources must have the same frequency (or wavelength) and a constant phase difference over time.
Step 1 (Governing Law & Condition for Interference): [1 Mark]
For two waves to produce a sustained interference pattern, they must be coherent. The fundamental condition for coherence is that the waves must have the same angular frequency ($\omega$). Given the wave equations in the form $y = a \sin(\omega t + \phi)$, the angular frequency is the coefficient of $t$.
- Wave (i): $\omega_1 = \omega$
- Wave (ii): $\omega_2 = 2\omega$
- Wave (iii): $\omega_3 = 2\omega$
- Wave (iv): $\omega_4 = 4\omega$
Step 2 (Step-by-Step Mathematical Working): [1 Mark]
We evaluate the pairs provided in the options based on the condition $\omega_a = \omega_b$:
- (A) (i) and (ii): $\omega_1 = \omega$ and $\omega_2 = 2\omega$. Since $\omega \neq 2\omega$, they cannot produce interference.
- (B) (ii) and (iii): $y_2 = a \sin(2\omega t)$ and $y_3 = a \sin(2\omega t + \phi)$. Here, both waves have the same angular frequency $2\omega$ and a constant phase difference $\phi$.
- (C) (iii) and (iv): $\omega_3 = 2\omega$ and $\omega_4 = 4\omega$. Since $2\omega \neq 4\omega$, they cannot produce interference.
- (D) (iv) and (i): $\omega_4 = 4\omega$ and $\omega_1 = \omega$. Since $4\omega \neq \omega$, they cannot produce interference.
Step 3 (Final Concluded Answer): [1 Mark]
Since only pair (ii) and (iii) possess the same angular frequency, they satisfy the condition for coherence. Therefore, the correct option is (B).
💡 EL10 Concept Insight: Think of interference like two people singing a note; if they sing at different pitches (frequencies), the sound just clashes and sounds messy. To get a steady, rhythmic "interference" pattern, they must sing the exact same note at the same pitch so their sound waves can perfectly overlap and reinforce or cancel each other out.